If the system of equations $2 x+3 y-z=5$ ; $x+\alpha y+3 z=-4$ ; $3 x-y+\beta z=7$ has infinitely many solutions, then $13 \alpha \beta$ is equal to
$1110$
$1120$
$1210$
$1220$
If the following system of linear equations
$2 x+y+z=5$
$x-y+z=3$
$x+y+a z=b$
has no solution, then :
The cubic $\left| {\begin{array}{*{20}{c}}
0&{a - x}&{b - x} \\
{ - a - x}&0&{c - x} \\
{ - b - x}&{ - c - x}&0
\end{array}} \right| = 0$ has a reperated root in $x$ then,
Solution of the equation $\left| {\,\begin{array}{*{20}{c}}1&1&x\\{p + 1}&{p + 1}&{p + x}\\3&{x + 1}&{x + 2}\end{array}\,} \right| = 0$ are
$2x + 3y + 4z = 9$,$4x + 9y + 3z = 10,$$5x + 10y + 5z = 11$ then the value of $ x$ is
Let $\lambda $ be a real number for which the system of linear equations $x + y + z = 6$
; $4x + \lambda y - \lambda z = \lambda - 2$ ; $3x + 2y -4z = -5$ Has indefinitely many solutions. Then $\lambda $ is a root of the quadratic equation